To get each committee pair having exactly 2 members in both, you need 10 + 8 + 6 + 4 + 2 = 30 members.
Each committee now has 10 members. Rules committee needs one more (chairman), which is 31 members.
Budget committee cannot have odd number of members and so it's limited to 10 members, not 11.
With 11 being maximum number of members in a committee, total number of members can vary from 31 to 35 and only 33 is divisible by 3 (third of the members are elected, which has to be a natural number).
So, the answer is B.
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Each committee now has 10 members. Rules committee needs one more (chairman), which is 31 members.
Budget committee cannot have odd number of members and so it's limited to 10 members, not 11.
With 11 being maximum number of members in a committee, total number of members can vary from 31 to 35 and only 33 is divisible by 3 (third of the members are elected, which has to be a natural number).
So, the answer is B.